If the maximum concentration of `PbCl_2` in water is 0.01 M at `25^@C`, its maximum concentration in 0.1 M NaCl will be

The solubility of PbCl_2 in water is 0.01 M at 25^@C it maximum concentration in 0.1M NaCl will be :

The solubility of PbCl_(2) in water is 0.01 M 25^(@) C. Its maximum concentration in 0.1 M NaCl will be :

The solubilituy of PbCI_(2) in water is 0.01M 25^(@)C . Its maximum concentration in 0.1M NaCI will be:

The reaction X to Product follows first order kinetics. In 40 minutes the concentration of X changes from 0.1 M to 0.025 M. Then the rate of reaction when concentration of X is 0.01 M will be

Calculate the change in pH when a 0.1 M solution of CH_3COOH in water at 25^@C is diluted to a final concentration of 0.01 M . [K_a=1.85xx10^(-5)]