If an em wave of wavelength `lambda` is incident on a photosenstive surface of negligible work function. If the photoelectrons emitted from this surface have the de-Broglie wavelength `lambda_1`, prove that
`lambda=((2mc)/h)lambda_1^2`

The de-Broglie wavelength lambda

An electromagnetic wave of length lambda is incident on a photosensitive surface of negligible work function. If the photoelectrons emitted from the surface have the same de-Broglie wavelength lambda , prove that lambda=(2mc)/h lambda_1^2

de-Broglie wavelength lambda is

An e-m wave of wavelength lambda is incident on a photo sensitive surface of negligible work function. If the photoelectrons emitted from this surface have the de-Broglie wavelength lambda_(1) . Find relation between 'lambda' and 'lambda_(1) '-

An e-m wave of wavelength lambda is incident on a photo sensitive surface of negligible work function. If the photoelectrons emitted from this surface have the de-Broglie wavelength lambda_(1) . Find relation between 'lambda' and 'lambda_(1) '-

An EM wave of waalength lambda is incident on a photosensitive surface of negligible work function. If m mass is of photo electron emitted from the surface has de-broglie wavelength lambda_d then,

An electromagnetic wave of wavelength lamda is incident on a photoelectrons emitted from this surface have the de Broglie wavelength lamda_(1) prove that lamda = ((2mc)/(h)) lamda_(1)^(2)