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1+2/(1+3/(2-1/(1+1/2)))...

`1+2/(1+3/(2-1/(1+1/2)))`

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lim_(nto oo) (1-1/(2^(2)))(1-1/(3^(2)))(1-1/(4^(2)))…………….(1-1/(n^(2))) equals:

(7)/(11)-"[1 (1)/(2)-[(1)/(2)+(1(3)/(4)-(1)/(2)+(1)/(3))]]

Find the value of (1-1/(2^(2)))(1-1/(3^(2)))(1-1/(4^(2)))(1-1/(5^(2)))…….(1-1/(9^(2)))(1-1/(10^(2)))

The product (1-(1)/(2^(2)))(1-(1)/(3^(2)))(1-(1)/(4^(2)))(1-(1)/(11^(2)))(1-(1)/(12^(2))) is equal to

The normal to the curve y(x-2)(x-3)=x+6 at the point where the curve intersects the y-axis , passes through the point : (1) (1/2,-1/3) (2) (1/2,1/3) (3) (-1/2,-1/2) (4) (1/2,1/2)

The normal to the curve y(x-2)(x-3)=x+6 at the point where the curve intersects the y-axis , passes through the point : (1) (1/2,-1/3) (2) (1/2,1/3) (3) (-1/2,-1/2) (4) (1/2,1/2)

The normal to the curve y(x-2)(x-3)=x+6 at the point where the curve intersects the y-axis , passes through the point : (1) (1/2,-1/3) (2) (1/2,1/3) (3) (-1/2,-1/2) (4) (1/2,1/2)

Using the mathematical induction, show that for any natural number, n ge 2,(1- 1/2^(2))(1-1/3^(2))(1-1/4^(2)). . .(1-1/n^(2))=(n+1)/(2n)

(1/2-:1/2 of 1/3)-:(1/2+1/2of 1/2)

The sum of the infinite series 1+(1+(1)/(2))((1)/(3))+(1+(1)/(2)+(1)/(2^(2)))((1)/(3^(2)))+...oo