The angular position of a point on the rim of a rotating wheel is given by `theta=4t^(3)-2t^(2)+5t+3` rad. Find
(a) the angular velocity at `t=1 s`,
(b) the angular acceleration at `t=2 s`.
(c ) the average angular velocity in time interval `t=0` to `t=2 s` and
(d) the average angular acceleration in time interval `t=1` to `t=3 s`.

The displacement of a particla moving in straight line is given by s=t^(4)+2t^(3)+3t^(2)+4 , where s is in meters and t is in seconds. Find the (a) velocity at t=1 s , (b) acceleration at t=2 s , (c ) average velocity during time interval t=0 to t=2 s and (d) average acceleration during time interval t=0 to t=1 s .

The angular displacement of a body is given by theta = 2t^(2) + 5t -3 . Find the value of the angular velocity and angular acceleration when t = 2s.

The angular position of a line of a disc of radius r = 6cm is given by theta=10 - 5t +4t^2 rad , the average angular velocity between 1 and 3s is

The angular position of a line of a disc of radius r = 6cm is given by theta=10 - 5t +4t^2 rad , the average angular velocity between 1 and 3s is

Find average speed in time interval t= 2 to t=10s

A angular positio of a point on the rim of a rotating wheel is given by theta=4t-3t^(2)+t^(3) where theta is in radiuans and t is in seconds. What are the angualr velocities at (a). t=2.0 and (b). t=4.0s (c). What is the average angular acceleration for the time interval that begins at t=2.0s and ends at t=4.0s ? (d). What are the instantaneous angular acceleration at the biginning and the end of this time interval?

A angular positio of a point on the rim of a rotating wheel is given by theta=4t-3t^(2)+t^(3) where theta is in radiuans and t is in seconds. What are the angualr velocities at (a). t=2.0 and (b). t=4.0s (c). What is the average angular acceleration for the time interval that begins at t=2.0s and ends at t=4.0s ? (d). What are the instantaneous angular acceleration at the biginning and the end of this time interval?

The instantaneous angular position of a point on a rotating wheel is given by the equation theta(t) = 2t^(3) - 6 t^(2) The torque on the wheel becomes zero at