If `intsec^(4//3)c "cosec"^(8//3)x dx =a(tanx)^(-5//3)+b(tanx)^(1//3)+C`, then 5a +b=

intsec^(6//5) x. "cosec"^(4//5) x dx

Evaluate: intsec^(4//3)x" cosec"^(8//3)xdx

Evaluate: intsec^(4//3)x" cosec"^(8//3)xdx

(3x+5)(1+tanx)

If int sec^(2) x "cosec"^(4) x dx =-1/3 cos^(3)x + k tanx - 2cot x+c , then k is equal to

If int(1)/(cos^(3)xsqrt(2 sin2x))dx=(tanx)^(A)+C(tanx)^(B)+k , where k is a constant of integration , the A+B+C equals

"If "int x^(5)(1+x^(3))^(2//3)dx=A(1+x^(3))^(8//3)+B(1+x^(3))^(5//3)+c, " then "

"If "int x^(5)(1+x^(3))^(2//3)dx=A(1+x^(3))^(8//3)+B(1+x^(3))^(5//3)+c, " then "

intx^(5)(1+x^(3))^(2//3)dx=A(1+x^(3))^(8//3)+B(1+x^(3))^(5//3)+c , then