Suppose R be the set of all real numbers and the mapping `f:R toR` is defined by `f(x)=2x^2-5x+6`. Find the value of `f^(-1)(3)`.

1 (a) answer any one question :(i) suppose IR be the set of all real no. and the mapping f:IR rarr IR is defined by f(x) = 2x^2-5x+6 . find the value of f^-1(3)

If R denotes the set of all real numbers then the mapping f:R to R defined by f(x)=|x| is -

Let R be the set of real numbers and f:R to R be defined by f(x)=2x^(2)-5x+6 , then the value of f^(-1)(2) is -

Let RR be the set of real numbers and the mapping f: RR rarr RR be defined by f(x)=2x^(2) , then f^(-1) (32)=

If R denotes the set of all real numbers then the function f: RtoR defined f(x) = |x|

If R denotes the set of all real numbers, then the function f : R to R defined by f (x) =[x] is

If R denotes the set of all real numbers, then the function f : R to R defined by f (x) =[x] is

Let R be the set of all real numbers. The function f:Rrarr R defined by f(x)=x^(3)-3x^(2)+6x-5 is