Calculate the nearest distance of approach of an `alpha`-particle of energy 2.5 Me V being scattered by a gold nucleus (Z=79).

Calculate distance of closet approach by an alpha -particle of KE=2.5 MeV being scattered by gold nucleus (Z=79) .

Calculate distance of closet approach by an alpha -particle of KE=2.5 MeV being scattered by gold nucleus (Z=79) .

Large angle scattering of alpha- particle led Rutherford to the discovery of atomic nucleus. It is the tiny central core of every atom in which entire positive charge of the atom is concentrated. The distance of closet approach of alpha particle from the nucleus is r_(theta)=((Ze)(2e))/(4pi epsilon_(theta)((1)/(2)mv^(2))) This distance r_(theta) gave him the order of size of nucleus. Read the above passage and answer the followign question: (i) What is the distance of closet approach of an alpha particle of energy 7.7 MeV from gold nucleus (z=79)? (ii) What is the implication of this relation in day to day life?

Calculate the distance of closest approach when a proton of energy 3 MeV approaches a gold nucleus (Z=79).

What is the impact parameter of an alpha -particle of initial energy 5 MeV scattered by 60^@ for Z=79 ?

What is the distance of closest approach to the nucleus for an alpha -particle of energy 5 MeV which undergoes scattering in the Gieger-Marsden experiment.

What is the distance of closest approach to the nucleus for an alpha -particle of energy 5J MeV which undergoes scattering in the Gieger-Marsden experiment.

Calculate the distance of closest approach for a proton with energy 3 MeV approaching a gold nucleus.