An elevator and its load wiegh a total of 1600 lb. Find the tension T in the supporting cable when the elevator, originally moving downwards at 20 ft/s is brought to rest with constant acceleration in a distance of 50 ft.

An elevator and its load weigh a total of 1600 kg. Find the tension T in the supporting cable when the elevator, originally moving downward at 20 m/s is brought to rest with constant acceleration in a distance of 50 m.

An elevator and its load weigh a total of 166 kg. Find the tension T in the supporting cable when the elevator, originally moving downwards at 20m//s is brought to rest with constant acceleration in a distance of 50 m.

An elevator and its load weigh a total of 800kg Find the tension T in the supporting cable when the elevator originally moving downwards at 20m//s is brought to rest with constant retardation in a distnce of 50m .

An elevator and it's load weight a total of 1600 kg. If the elevator originially moving downward at 20 m/sec is brought to rest with constant acceleration in a distance of 50 m, then tension T is how much

An elevator and its load have a total mass of 800 kg. If the elevator, originally moving downwards at 10 ms^(-1) , is brought to rest with constant deceleration in a distance of 25 m, the tension in the supporting cable will be ( g=10 ms^(-2) )

An elevator and its load have a total mass of 800 kg. If the elevator, originally moving downwards at 10 ms^(-1) , is brought to rest with constant deceleration in a distance of 25 m, the tension in the supporting canble will be ( g=10 ms^(-2) )

An elevator and its load have a total mass of 800 kg. If the elevator, originally moving downwards at 10 ms^(-1) , is brought to rest with constant deceleration in a distance of 25 m, the tension in the supporting canble will be ( g=10 ms^(-2) )

An elevator weighs 4000kg When the upward tension in the supporting cable is 48000 N what is the upward acceleration? Starting from rest, how far does it rise in 3 seconds ?

A motor car starts from rest and accelerates uniformly for 10 s to a velocity of 20 ms^(-1) . It then runs at a constant speed and is finally brought to rest in 40 m with a constant acceleration. Total distance covered is 640 m. Find the value of acceleration, retardation and total tie taken.