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In the given figure, `O` is the centre of a circle . If `/_ OAC = 50^(@)` then `/_ OBD = ?`

A

`40^(@)`

B

`50^(@)`

C

`60^(@)`

D

`75^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B
`/_ ODB = /_ OAC = 50^(@) ( /_ s`in the same segment).
Now, `OB = OD ` ( radii of the same circle )
`implies /_ OBD = /_ ODB = 50^(@)`
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