What length of tarpaulin 3m wide will be required to make a conical tent of height 8m and base radius 6m? Assume that the extra length of material will be required for stitching margins and wastage in cutting is approximately 20 cm `(U s e\ pi=3. 14)`

Explanation

Base radius of the tent, `r = 6m` and its height, `h = 8m`
`:. l= sqrt(r^(2) + h^(2)) = sqrt(6^(2) + 8^(2)) m = sqrt(36 + 64) m`
`= sqrt(100)m = 10m`
Curved surface area of the conical tent
`= pi rl = (3.14 xx 6 xx 10) m^(2) = 188.4 m^(2)`
Area of tarpaulin required `= 188.4 m^(2)`
Width of tarpaulin = 3m
Length of tarpaulin `= ("area")/("width") = (188.4)/(3) m = 62.8m`
Extral length required `= 20 cm = (20)/(100) m = 0.2m`
Total length of tarpaulin required `= (62.8 + 0.2) m = 63m`