How many spherical bullets can be made out of a solid cube of lead whose edge measures `44 cm,` each being `4 cm` in diameter.

Explanation

Length of each edge of the cube `= 44 cm`
Volume of the cube `= (44 xx 44 xx 44) cm^(3)`
Radius of each bullet, `r = 2 cm`
Volume of each bullet `=((4)/(3) pi r^(3)) cm^(3)`
`= ((4)/(3) xx (22)/(7) xx 2 xx 2 xx 2) cm^(3) = (704)/(21) cm^(3)`
Number of bullets formed `= ("volume of the cube in " cm^(3))/("volume of each bullet in " cm^(3))`
`= (44 xx 44 xx 44 xx (21)/(704)) = 2541`
Hence, the number of bullets formed is `2541.`