Tow solid spheres made of the same metal have weight `5920 g` and `740 g,` respectively. Determine the radius of the radius of the larger sphere, if the diameter of the smaller one is `5 cm.`

Explanation

Let d `g//cm^(3)` be the density of the given metal and let the radius of the larger sphere be `R` cm
Radius of smaller sphere `= 2.5 cm.`
Now, `("volume of larger spher " xx d)/("volume of smaller sphere " xx d) = (5920)/(740)`
`rArr ((4)/(3) pi R^(3) xxd)/((4)/(3) pi ((5)/(2))^(3) xxd)= 8 rArr R^(3) = 8 xx ((5)/(2))^(3) = (8 xx 125)/(8) = 125`
`rArr R^(3) = 5^(3) rArr R = 5 cm`
Hence, the radius of the larger sphere is `5 cm.`