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A wall 15 m long, 30 cm wide and 4m high...

A wall 15 m long, 30 cm wide and 4m high is made of bricks, each measuring `(22cm xx 12.5 cm xx 7.5 cm)`. If `(1)/(12)` of the total volume of the wall consits of mortar, how many bricks are there in the wall ?

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To find the number of bricks in the wall, we will follow these steps: ### Step 1: Calculate the Volume of the Wall The volume \( V \) of a cuboid is given by the formula: \[ V = \text{length} \times \text{breadth} \times \text{height} \] Given: - Length = 15 m - Breadth = 30 cm = 0.30 m (since 1 m = 100 cm) - Height = 4 m Now, substituting the values: \[ V = 15 \, \text{m} \times 0.30 \, \text{m} \times 4 \, \text{m} \] \[ V = 15 \times 0.30 \times 4 = 18 \, \text{m}^3 \] ### Step 2: Calculate the Volume of Mortar According to the problem, \(\frac{1}{12}\) of the total volume of the wall consists of mortar. \[ \text{Volume of Mortar} = \frac{1}{12} \times \text{Volume of Wall} \] Substituting the volume of the wall: \[ \text{Volume of Mortar} = \frac{1}{12} \times 18 \, \text{m}^3 = 1.5 \, \text{m}^3 \] ### Step 3: Calculate the Volume of Bricks The volume occupied by bricks is the total volume of the wall minus the volume of mortar: \[ \text{Volume of Bricks} = \text{Volume of Wall} - \text{Volume of Mortar} \] \[ \text{Volume of Bricks} = 18 \, \text{m}^3 - 1.5 \, \text{m}^3 = 16.5 \, \text{m}^3 \] ### Step 4: Calculate the Volume of One Brick The volume \( V_b \) of one brick is given by: \[ V_b = \text{length} \times \text{breadth} \times \text{height} \] Given the dimensions of the brick: - Length = 22 cm = 0.22 m - Breadth = 12.5 cm = 0.125 m - Height = 7.5 cm = 0.075 m Now substituting the values: \[ V_b = 0.22 \, \text{m} \times 0.125 \, \text{m} \times 0.075 \, \text{m} \] \[ V_b = 0.22 \times 0.125 \times 0.075 = 0.00020625 \, \text{m}^3 \] ### Step 5: Calculate the Number of Bricks To find the number of bricks, we divide the total volume of bricks by the volume of one brick: \[ \text{Number of Bricks} = \frac{\text{Volume of Bricks}}{\text{Volume of One Brick}} \] \[ \text{Number of Bricks} = \frac{16.5 \, \text{m}^3}{0.00020625 \, \text{m}^3} \] Calculating this gives: \[ \text{Number of Bricks} \approx 79999.999 \approx 80000 \] ### Final Answer Thus, the number of bricks in the wall is approximately **80000**. ---

To find the number of bricks in the wall, we will follow these steps: ### Step 1: Calculate the Volume of the Wall The volume \( V \) of a cuboid is given by the formula: \[ V = \text{length} \times \text{breadth} \times \text{height} \] Given: ...
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RS AGGARWAL-VOLUME AND SURFACE AREA OF SOLIDS-Exercise 15A
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  11. Find the volume, the lateral surface area, the total surface area and ...

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  12. The total surface area of a cube is 1176 cm^(2). Find its volume

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  13. The lateral surface area of a cube is 900 cm^(2). Find its volume

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  14. The volume of a cube is 512 cm^(3). Its total surface area is

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  15. Three cubes of metal with edges 3cm, 4 cm and 5 cm respectively are me...

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  19. If V is the volume of a cuboid of dimensions a ,\ b ,\ c\ a n d\ S ...

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