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A classroom is 10 m long, 6.4 m wide and...

A classroom is 10 m long, 6.4 m wide and 5m high. If each student be given `1.6 m^(2)` of the floor area, how many students can be accommodated in the room ? How many cubic metres of air would each student get ?

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To solve the problem, we will follow these steps: ### Step 1: Calculate the area of the classroom floor. The area of a rectangle is given by the formula: \[ \text{Area} = \text{Length} \times \text{Width} \] Given: - Length = 10 m - Width = 6.4 m Calculating the area: \[ \text{Area} = 10 \, \text{m} \times 6.4 \, \text{m} = 64 \, \text{m}^2 \] ### Step 2: Determine how many students can be accommodated. Each student requires an area of: \[ 1.6 \, \text{m}^2 \] To find the number of students that can be accommodated, we divide the total area of the classroom by the area required per student: \[ \text{Number of students} = \frac{\text{Total Area}}{\text{Area per student}} \] \[ \text{Number of students} = \frac{64 \, \text{m}^2}{1.6 \, \text{m}^2} \] Calculating: \[ \text{Number of students} = 40 \] ### Step 3: Calculate the volume of the classroom. The volume of a cuboid is given by the formula: \[ \text{Volume} = \text{Length} \times \text{Width} \times \text{Height} \] Given: - Height = 5 m Calculating the volume: \[ \text{Volume} = 10 \, \text{m} \times 6.4 \, \text{m} \times 5 \, \text{m} \] \[ \text{Volume} = 320 \, \text{m}^3 \] ### Step 4: Calculate the volume of air available per student. To find out how much air each student gets, we divide the total volume of the classroom by the number of students: \[ \text{Volume of air per student} = \frac{\text{Total Volume}}{\text{Number of students}} \] \[ \text{Volume of air per student} = \frac{320 \, \text{m}^3}{40} \] Calculating: \[ \text{Volume of air per student} = 8 \, \text{m}^3 \] ### Final Answers: - Number of students that can be accommodated: **40** - Volume of air each student gets: **8 m³** ---

To solve the problem, we will follow these steps: ### Step 1: Calculate the area of the classroom floor. The area of a rectangle is given by the formula: \[ \text{Area} = \text{Length} \times \text{Width} \] Given: - Length = 10 m ...
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RS AGGARWAL-VOLUME AND SURFACE AREA OF SOLIDS-Exercise 15A
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  3. How many cubic centimetres of iron are there in an open box whose e...

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  4. A box made of sheet metal costs 6480at 120per square metre.If the box...

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  5. The volume of a cuboid is 1536 m^(3). Its length is 16m, and its bread...

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  6. How many person can be accommodated in a dining hall of dimensions (20...

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  7. A classroom is 10 m long, 6.4 m wide and 5m high. If each student be g...

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  8. The surface area of a cuboid is 758 cm^(2). Its length and breadth are...

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  9. In a shower, 5 cm of rain falls. Find the volume of water that falls o...

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  10. Find the volume, the lateral surface area, the total surface area and ...

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  11. The total surface area of a cube is 1176 cm^(2). Find its volume

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  12. The lateral surface area of a cube is 900 cm^(2). Find its volume

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  13. The volume of a cube is 512 cm^(3). Its total surface area is

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  14. Three cubes of metal with edges 3cm, 4 cm and 5 cm respectively are me...

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  15. The length of the longest rod that can be placed in a room of dimensio...

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  16. The sum of length, breadth and depth of a cuboid is 19\ c m and length...

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  17. Each edge of a cube is increased by 50%. Find the percentage increa...

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  18. If V is the volume of a cuboid of dimensions a ,\ b ,\ c\ a n d\ S ...

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  19. Water in a canal, 30\ d m\ w i d e\ a n d\ 12 d m\ d e e p ,\ is f...

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  20. A solid metallic cuboid of dimensions 9m xx 8m xx2 is melted and recas...

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