The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm3 of wood has a mass of 0.6 g.

Answer

3.432 kg

Explanation

Volume of the pipe `= {pi (R^(2) - r^(2)) xx h}`
`= [(22)/(7) xx {(14)^(2) - (12)^(2)} xx 35] cm^(3) = 5720 cm^(3)`
Mass of the pipe `= (5720 xx (6)/(10) xx (1)/(1000)) kg = 3.432 kg`