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a hemispherical bowl is made of steel 0.5 cm thick. The inside radius of the bowl is 4 cm. Find the volume of steel used in making the bowl.

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The correct Answer is:
`56.83 cm^(3)`
Inner radius , r = 4 cm, and outer radius, R = 4.5 cm
Volume of steel `= (2)/(3) pi xx [(4.5)^(3) - (4)^(3)] cm^(3) = 56.83 cm^(3)`
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RS AGGARWAL-VOLUME AND SURFACE AREA OF SOLIDS-Exercise 15D
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