A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs 32 per `100 cm^(2)`.

Answer

Rs 55.44

Explanation

Inner radius `= (21)/(4) cm`
Inner curved surface area `= (2 xx (22)/(7) xx (21)/(4) xx (21)/(4))cm^(2) = 173.25 cm^(2)`
Cost of tin-plating `Rs (173.25 cc (32)/(100)) = Rs 55.44`