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A cone is 8.4 cm heigh and the radius of...

A cone is 8.4 cm heigh and the radius of its base is 2.1 cm. It is melted and recast into a sphere. The radius of the sphere is

A

4.2 cm

B

2.1 cm

C

2.4 cm

D

1.6 cm

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The correct Answer is:
To find the radius of the sphere formed by melting a cone, we will first calculate the volume of the cone and then set it equal to the volume of the sphere. ### Step-by-Step Solution: 1. **Calculate the Volume of the Cone**: The formula for the volume \( V \) of a cone is given by: \[ V = \frac{1}{3} \pi r^2 h \] where \( r \) is the radius of the base and \( h \) is the height of the cone. Here, \( r = 2.1 \) cm and \( h = 8.4 \) cm. Plugging in these values: \[ V = \frac{1}{3} \pi (2.1)^2 (8.4) \] 2. **Calculate \( (2.1)^2 \)**: \[ (2.1)^2 = 4.41 \] 3. **Substitute back into the volume formula**: \[ V = \frac{1}{3} \pi (4.41)(8.4) \] 4. **Calculate \( 4.41 \times 8.4 \)**: \[ 4.41 \times 8.4 = 37.044 \] 5. **Now calculate the volume**: \[ V = \frac{1}{3} \pi (37.044) \] \[ V = \frac{37.044}{3} \pi = 12.348 \pi \text{ cm}^3 \] 6. **Volume of the Sphere**: The formula for the volume \( V \) of a sphere is given by: \[ V = \frac{4}{3} \pi r^3 \] Setting the volume of the cone equal to the volume of the sphere: \[ 12.348 \pi = \frac{4}{3} \pi r^3 \] 7. **Cancel \( \pi \) from both sides**: \[ 12.348 = \frac{4}{3} r^3 \] 8. **Multiply both sides by \( \frac{3}{4} \)** to isolate \( r^3 \): \[ r^3 = 12.348 \times \frac{3}{4} \] \[ r^3 = 9.261 \] 9. **Calculate the cube root of both sides to find \( r \)**: \[ r = \sqrt[3]{9.261} \approx 2.1 \text{ cm} \] ### Final Answer: The radius of the sphere is approximately \( 2.1 \) cm.
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RS AGGARWAL-VOLUME AND SURFACE AREA OF SOLIDS-Multiple Choice Questions (Mcq)
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