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In the adjoining figure, ABCD is a squar...

In the adjoining figure, ABCD is a square and `triangle `EDC is an equilateral triangle. Proove that
(i) `AE=BE, " (ii) " angle DAE=15^(@).`

Text Solution

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`triangle ADE ~= triangle BCE " "[ because AD=BC,DE=CE, angle ADE=angle BCE=(90^(@)+60^(@))]`
`therefore AE=BE.`
Now, `angle ADE =150^(@) and DA=DE rArr angle DAE = angle DEA =15^(@).`
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