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In a parallelogram PQRS, PQ = 12 cm and ...

In a parallelogram PQRS, PQ = 12 cm and PS = 9 cm. The bisector of `angle P` meet SR in M. PM and QR both when produced meet at T. Find the length of RT.

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The correct Answer is:
3 cm

`angle QPM= angle SPM= theta (because PM " is besector of " angle P)`
`angle QPM = angle PMS= theta ("alt. interior " angle) rArr PS= SM=9cm. `
`angle RMT = angle PMS=theta ("vert. opposite "angle )`
`angle RTM=angle SPM=theta ("alt. interior " angle)`
`rArr RT=RM=SR -SM =(12-9)cm =3cm.`
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