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In the given figure, ABCD is a parallelo...

In the given figure, ABCD is a parallelogram, M is the midpoint of BD and BD bisects `angle B` as well as `angle D`. Then, `angle AMB=`?

A

`45^(@)`

B

`60^(@)`

C

`90^(@)`

D

`30^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
`angle B=angle D rArr (1)/(2)angle B=(1)/(2)angle D rArr angle ADB= angle ABD.`
`therefore triangle ABD` is isosoceles and M is the midpoint of BD.
`therefore AM bot BD " and hence " angle AMB =90^(@)`.
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