Home
Class 9
MATHS
In the given figure, DeltaABC is an isos...

In the given figure, `DeltaABC` is an isosceles triangle in which AB=AC and AE bisects `angleCAD`. Prove that `AE||BC`.

Text Solution

AI Generated Solution

To prove that \( AE \parallel BC \) in triangle \( \Delta ABC \) where \( AB = AC \) and \( AE \) bisects \( \angle CAD \), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Information**: - \( \Delta ABC \) is an isosceles triangle with \( AB = AC \). - \( AE \) bisects \( \angle CAD \). ...
Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    RS AGGARWAL|Exercise EXAMPLE|10 Videos

  • TRIANGLES

    RS AGGARWAL|Exercise Exercise 8|13 Videos

  • QUADRILATERALS

    RS AGGARWAL|Exercise Matching of Columns:|2 Videos

  • VOLUME AND SURFACE AREA OF SOLIDS

    RS AGGARWAL|Exercise Multiple Choice Questions (Mcq)|73 Videos

Similar Questions

Explore conceptually related problems

In the adjoining figure, DeltaABC is an isosceles triangle in which AB = AC and AD is the bisector of angleA . Prove that: DeltaADB~=DeltaADC

In the adjoining figure, DeltaABC is an isosceles triangle in which AB = AC and AD is the bisector of angleA . Prove that: BD = CD

In the adjoining figure, DeltaABC is an isosceles triangle in which AB = AC and AD is the bisector of angleA . Prove that: ADbotBC

In the adjoining figure, DeltaABC is an isosceles triangle in which AB = AC and AD is the bisector of angleA . Prove that: angleB=angleC

In the adjoining figure, DeltaABC is an isosceles triangle in which AB = AC and AD is a median. Prove that: DeltaADB~=DeltaADC

In the adjoining figure, DeltaABC is an isosceles triangle in which AB = AC and AD is a median. Prove that: angleBAD=angleCAD

In the adjoining figure, DeltaABC is an isosceles triangle in which AB = AC. If BMbotACandCNbotAB , prove that: BM = CN

In the adjoining figure, DeltaABC is an isosceles triangle in which AB = AC. If BMbotACandCNbotAB , prove that: DeltaBMC~=DeltaCNB

In the adjoining figure, ABC is an isosceles triangle in which AB = AC. Also, D is a point such that BD = CD. Prove that AD bisects /_ A and /_D