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In the given figure, side BC of DeltaABC...

In the given figure, side BC of `DeltaABC` is produced to D. If `angleACD=128^(@)andangleABC=43^(@),"find "angleBACandangleACB`

Text Solution

Verified by Experts

The correct Answer is:
`angleBAC=85^(@),angleACB=52^(@)`
`angleBAC+angleABC=ext.angleACDimpliesangleBAC+43^(@)=128^(@)impliesBAC=85^(@)`
Also, `angleBAC+angleABC+angleACB=180^(@)."Find "angleACB`.
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Knowledge Check

  • The side BC of Delta ABC is produced to D. If angleACD = 108^(@) and angleB = 1/2 angleA then angleA is

    A
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    B
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    C
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    B
    `40^(@)`
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    D
    `20^(@)`

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    `30^(@)`
    B
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    C
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    D
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