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In the given figure, AB||CDandEF is a tr...

In the given figure, `AB||CDandEF` is a transversal. If `angleAEF=65^(@),angleDFG=30^(@),angleEGF=90^(@)andangleGEF=x^(@),` find the value of x.

Text Solution

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The correct Answer is:
x=55
`angleEFD=angleAEF=65^(@)" "["altermate"angles]`
`:.angleEFG=(65^(@)-30^(@))=35^(@),angleFGE=90^(@)`
In `DeltaEFG,` we have `35^(@)+90^(@)+x^(@)=180^(@)impliesx=55^(@)`.
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