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Side BC of DeltaABC has been produced to...

Side BC of `DeltaABC` has been produced to D on left and to E on right-hand side of BC such that `angleABD=106^(@)andangleACE=118^(@)." Then, "angleA=?`

A

`44^(@)`

B

`55^(@)`

C

`65^(@)`

D

`75^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`angleABC=(180^(@)-125^(@))=55^(@)andangleACB=(180^(@)-130^(@))=50^(@)`.
`angleA+angleB+angleC=180^(@)impliesangleA=+55^(@)+50^(@)=180^(@)`
`impliesangleA=(180^(@)-105^(@))=75^(@)`.
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