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In the given figure, BO and CO are the b...

In the given figure, BO and CO are the bisectors of `angleBandangleC` respectively. If `angleA=50^(@)" then "angleBOC=?`

A

`130^(@)`

B

`100^(@)`

C

`115^(@)`

D

`120^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
`angleB+angleC=(180^(@)-angleA)=(180^(@)-150^(@))=130^(@)`
`(1)/(2)angleB+(1)/(2)angleC=((1)/(2)xx130^(@))=65^(@)`
`(1)/(2)angleB+(1)/(2)angleC+angleBOC=180^(@)implies65^(@)+angleBOC=180^(@)impliesangleBOC=115^(@)`.
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