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The mean of 100 iterms was found to be 6...

The mean of 100 iterms was found to be 64. Later on it was discovered that two items were misread as 26 and 9 instead of 36 and 90 respectively. Find the correct mean.

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Mean of 100 items, as calculated = 64
Sum of 100 items, as calculated = `( 64 xx 100) = 6400`
Correct sum of 100 items
= ( 6400 -( sum of wrong items ) +( sum of correct iterms) )
= { 6400 -(26 +9) +(36 +90)}
= ( 6400 -35 +126) = ( 6526 -35) = 6491.
Correct mean =` ((6491)/100) = 64.91 `
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RS AGGARWAL-MEAN , MEDIAN AND MODE OF UNGROUPED DATA -Multiple Choice Questions (Mcq)
  1. The mean of 100 iterms was found to be 64. Later on it was discovered ...

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  2. If the mean of five observations x ,\ x+2,\ x+4,\ x+6,\ x+8\ i s\ 11...

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  3. If the mean of the observation x, x+3, x+5, x+7 and x+10 is 9, then me...

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  4. if overlinex is the mean of x(1),x(2),x(3),….,x(n) " then "sum(n)^(i=1...

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  5. If each observation of the data is decreased by 8 then their mean

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  6. The mean weight of 6 boys in a group is 48 kg. the individual weight o...

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  7. The mean of the marks scored by 50 students was found to be 39 later o...

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  8. The mean of 100 items was found to be 64. Later on it was discovered t...

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  9. The mean of 100 observation is 50. If one of the observation which was...

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  10. Let barx be the mean of x(1), x(2), ………, x(n) and bary be the mean of ...

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  11. If barx is the mean of x(1), x(2), …………., x(n), then for a ne 0, the m...

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  12. If barx(1), barx(2), barx(3),………barx(n) are the means of n groups with...

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  13. The mean of the following data is 8. Then, the value of p is

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  14. The runs scored by 11 members of a cricket team are 15,34,56,27,43,...

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  15. The weight of 10 students (in kg) are 55,40,35,52,60,38,36,45,31,44....

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  16. The median of the numbers 4,4,5,6,7,7,12,3,12 is

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  17. The median of the numbers 84,78,54,56,68,22,34,45,39,54 is

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  18. Mode of the data 15,17,19,14,18,15,14,20,19,14,15,19,14 is

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  19. The median of the data arranged in ascending order 8,9,12,18,(x+2),(x+...

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