`p(-3) = 0` then p(x) = ………..

p(x) = x^2-3x+2 then p(0)=

A random variable X takes the values 0,1,2,3 and its mean = 1,3 .If P(X=3) =2P(X=1) and P(X=2) = 0.3 then P(X=0) is

A random variate X takes the values 0, 1, 2, 3 and its mean is 1.3. If P(X= 3) = 2P(X= 1) and P(X= 2) = 0.3 , then P(X= 0) is equal to

A random variable X takes the values 0, 1, 2, 3 and its mean is 1.3 . If P(X= 3) = 2P(X= 1) and P(X= 2) = 0.3 , then P(X= 0) is equal to

(x-3) is a factor of p(x) , if p(_) =0

(1 + x)^(n) = p_(0) + p_(1) x + p_(2) x^(2) + … + p_(n) x^(n) , then p_(0) + p_(3) + p_(6) + ….. =

px+3y-(p-3)=0, 12x+py-p=0 has infinitely many solutions then p=………….