`Ice at -20^(@)C` is added to 50 g of water at `40 ^(2)C` When the temperature of the mixture reaches `0^(@) C` it is found that 20 g of ice is still unmelted .The amount of ice added to (Specific heat of water `=4.2 j//g//^(@)C`
Specific heat of Ice `=2.1 J//g //^(@)C` M
Heat of fusion of water of `0^(@)C=334 J//g)`

Ice at 20^(@)C is added to 50 g of water at 40^(@) . When the temperaurtre of the mixture reaches 0^(@)C , it is observed that 20 g of ice is still unmelted. The amount (in gram) of ice added to the water was (Specific heat of water =4.2J//g//""^(@)C Specific heat of ice =2.1J//g//""^(@)C Heat of fusion of water at 0^(@)C=334J//g)

X g of ice at 0 .^(@)C is added to 340 g of water at 20^(@)C. The final tempeature of the resultant mixture is 5 .^(@)C. The value of X (in g) is closest to [Heat of fusion of ice = 333 J//g, Specific heat of water = 4.184 J//g. K ]

The temperature of 300 g of water at 40^@ C is lowered to 0^@ C by adding ice to it. Find the mass of ice added if specific heat capacity of water is 4.2 J g^(-1) K^(-1) and specific latent heat of ice is 336 J g^(-1)

104 g of water at 30^@ C is taken in a calorimeter made of copper of mass 42 g. When a certain mass of ice at 0°C is added to it, the final steady temperature of the mixture after the ice has melted, was found to be 10^@ C. Find the mass of ice added. [Specific heat capacity of water = 4.2 J g^(-1)""^@ C^(-1) , Specific latent heat of fusion of ice = 336 J g^(-1) , Specific heat capacity of copper = 0.4 Jg^(-1) ""^@ C^(-1) ].

What amount of ice will remains when 52 g ice is added to 100 g of water at 40^(@)C ? Specific heat of water is 1 cal/g and latent heat of fusion of ice is 80 cal/g.

50 g of ice at 0^@C is mixed with 50 g of water at 80^@C . The final temperature of the mixture is (latent heat of fusion of ice =80 cal //g , s_(w) = 1 cal //g ^@C)

50 g of ice at 0^@C is mixed with 50 g of water at 80^@C . The final temperature of the mixture is (latent heat of fusion of ice =80 cal //g , s_(w) = 1 cal //g ^@C)