The acceleration of a particle executing SHM at a distance of 3 cm from equilibrium position is `5 cm//s^(2)`. Its acceleration at a distance of 2 cm from equilibrium position is

The P.E. of a particle executing SHM at a distance x from its equilibrium position is

The P.E. of a particle executing SHM at a distance x from its equilibrium position is

Acceleration of a particle, executing SHM, at it’s mean position is

Acceleration of a particle, executing SHM, at it’s mean position is

The amplitude of a particle executing SHM is 0.1 m. The acceleration of the particle at a distance of 0.03 m from the equilibrium position is 0.12m*s^(-2) . What will be its velocity at a distance of 0.08 m from the position of equilibrium?

What is the acceleration of a particle executing S.H.M. at its mean position.?

The acceleration of a particle executing S.H.M, when it is at its mean position is

Time period and amplitude of a particle executing SHM are 2 s and 5 cm respectively. Determine its velocity and acceleration at a distacne of 3 cm from the equilibrium position.

The acceleration of a particle performing SHM is 12cm//s^2 at a distance of 3 cm from the mean position. Calculate its time-period.

The acceleration of a particle performing S.H.M. is 12 cm/ s^(2) at a distance of 3 cm from the mean position. Its time period is _____ .