Find the HCF and LCM of 126 and 156 using prime factorisation method.

Explanation

We have .

` 126 = ( 2xx 3 xx 3xx 7) = (2xx 3^(2) xx 7)`
and ` 156= ( 2xx 2xx 3 xx 13) = ( 2^(2) xx 3 xx 13)`
HCF ( 126 , 156) = product of common terms with lowest power
`=( 2^(1) xx 3^(1) ) = ( 2 xx 3) = 6`
and LCM ( 126, 156) = product of prime factors with highest power
` ( 2 ^(2) xx 3^(2) xx 7 xx 13) = ( 4 xx 9xx7xx13)`
=3276 .
HCF = 6 and LCM = 3276