Find the HCF and LCM of 108,120 and 252 using prime factorisation method.

Explanation

By prime factorisation , we get
` 108 = ( 2^(2) xx 3^(3)`
` 120 = ( 2^(3) xx 3 xx5)`
` 252 = ( 2 ^(2) xx 3^(2)xx 7)`
HCF ( 108,120,252) = product of common terms with lowest power
` (2^(2) xx3) = ( 4 xx 3) =12`
LCM ( 108,120,252) = product of prime factors with highest power
` = ( 2^(2) xx 3^(3) xx 5xx7) = 7560`
`HCF = 12 and LCM = 7560`