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LCM of ( 2^(3) xx 3 xx5) and ( 2^(4) xx ...

LCM of `( 2^(3) xx 3 xx5) and ( 2^(4) xx 5xx 7) ` is

A

40

B

560

C

1120

D

1680

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AI Generated Solution

The correct Answer is:
To find the LCM of the numbers \(2^3 \times 3 \times 5\) and \(2^4 \times 5 \times 7\), we can follow these steps: ### Step 1: Identify the prime factors and their powers - For the first number \(A = 2^3 \times 3^1 \times 5^1\): - The prime factors are: - \(2\) with power \(3\) - \(3\) with power \(1\) - \(5\) with power \(1\) - For the second number \(B = 2^4 \times 5^1 \times 7^1\): - The prime factors are: - \(2\) with power \(4\) - \(5\) with power \(1\) - \(7\) with power \(1\) ### Step 2: Determine the highest power of each prime factor - For the prime factor \(2\): - The highest power is \(4\) (from \(B\)). - For the prime factor \(3\): - The highest power is \(1\) (from \(A\)). - For the prime factor \(5\): - The highest power is \(1\) (both \(A\) and \(B\) have \(5^1\)). - For the prime factor \(7\): - The highest power is \(1\) (from \(B\)). ### Step 3: Write the LCM using the highest powers Now, we can write the LCM as: \[ \text{LCM} = 2^4 \times 3^1 \times 5^1 \times 7^1 \] ### Step 4: Calculate the LCM 1. Calculate \(2^4\): \[ 2^4 = 16 \] 2. Calculate \(3^1\): \[ 3^1 = 3 \] 3. Calculate \(5^1\): \[ 5^1 = 5 \] 4. Calculate \(7^1\): \[ 7^1 = 7 \] 5. Now multiply these results together: \[ \text{LCM} = 16 \times 3 \times 5 \times 7 \] 6. Calculate \(16 \times 3\): \[ 16 \times 3 = 48 \] 7. Calculate \(48 \times 5\): \[ 48 \times 5 = 240 \] 8. Finally, calculate \(240 \times 7\): \[ 240 \times 7 = 1680 \] ### Final Answer: The LCM of \(2^3 \times 3 \times 5\) and \(2^4 \times 5 \times 7\) is \(1680\). ---

To find the LCM of the numbers \(2^3 \times 3 \times 5\) and \(2^4 \times 5 \times 7\), we can follow these steps: ### Step 1: Identify the prime factors and their powers - For the first number \(A = 2^3 \times 3^1 \times 5^1\): - The prime factors are: - \(2\) with power \(3\) - \(3\) with power \(1\) - \(5\) with power \(1\) ...
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