Home
Class 10
MATHS
( k - 1 ) x - y = 5, (k + 1 ) x +...

` ( k - 1 ) x - y = 5`,
` (k + 1 ) x + ( 1 - k ) y = ( 3k + 1 )`

Text Solution

Verified by Experts

The correct Answer is:
` k = 3 `
Promotional Banner

Topper's Solved these Questions

  • LINEAR EQUATIONS IN TWO VARIABLES

    RS AGGARWAL|Exercise Exercise 3E|53 Videos

  • LINEAR EQUATIONS IN TWO VARIABLES

    RS AGGARWAL|Exercise Exercise 3F|21 Videos

  • LINEAR EQUATIONS IN TWO VARIABLES

    RS AGGARWAL|Exercise Exercise 3C|13 Videos

  • HEIGHTS AND DISTANCES

    RS AGGARWAL|Exercise Multiple Choice Questions (Mcq)|25 Videos

  • MEAN,MEDAN,MODE OF GROUPED,DATA CUMULATIVE FREQUENCY GRAPH AND OGIVE

    RS AGGARWAL|Exercise Test Yourself|18 Videos

Similar Questions

Explore conceptually related problems

5x + 2y = 2k , 2 (k + 1 ) x + ky = (3k + 4)

Find the values of k for which the following pair of linear equations has infinitely many solutions : 2x - 3y = 7, ( k + 1 ) x + ( 1 - 2k) y = ( 5k - 4) .

det [[x ^ (k), x ^ (k + 2), x ^ (k + 3) y ^ (k), y ^ (k + 2), y ^ (k + 3) z ^ (k) , z ^ (k + 2), z ^ (k + 3)]] = (xy) (yz) (zx) {(1) / (x) + (1) / (y) + (1) / ( from)}

Y = sum_ (k = 0) ^ (5) x ^ (k) a ^ (k-1)

{:(2x + (k - 2)y = k),(6x + (2k - 1) y = 2k + 5):}

{:(2x + 3y = 2),((k + 2)x + (2k + 1)y = 2(k - 1)):}

For how many values of k. will the system of equations (k + 1) x + 8y = 4k and kx + (k + 3) y = 3k - 1 , have an infinite number of solutions

if the lines (x - 1)/(-3) = ( y - 2)/(2k) = ( z -3)/(2) and (x -1) /(3k) = ( y - 5)/(1) = (z - 6 ) /(-5) are at night angle , then find the value of k .

If the lines (x -1)/(-3) = (x - 2)/(2k) = (z - 3)/(2) and (x - 1)/(3k ) = (y -1)/(1) = (z - 6)/(-5) are perpendicular to each other, then the value of k is ,