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{:((k - 3)x + 3y = k),(kx + ky = 12):}...

`{:((k - 3)x + 3y = k),(kx + ky = 12):}`

Text Solution

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The correct Answer is:
`k = 6`
`(k - 3)/(k) = ( 3) /(k) = ( -k )/(- 12 ) rarr ( k - 3 ) /( k ) = ( 3)/(k) and ( 3) /( k ) = ( k ) /( 12)`
` therefore k ^(2) - 6k = 0 and k ^(2) = 36 rArr k ( k - 6) = 0 and k ^(2) = 36`
` rArr ( k = 0 or k = 6) and ( k = 6 or k = - 6)`
` rArr k = 6 `.
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