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Places A and B are 160 km apart on a hi...

Places A and B are 160 km apart on a highway. One car starts from A and another from B at the same time. If they travel in the same direction, they meet in 8 hours. But, if they travel towards each other, they meet in 2 hours. Find the speed of each car.

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To solve the problem, we need to find the speeds of two cars traveling between places A and B, which are 160 km apart. We will denote the speed of the first car as \( x \) km/h and the speed of the second car as \( y \) km/h. ### Step 1: Set up the equations based on the given information. 1. **Same Direction:** When both cars travel in the same direction, they meet after 8 hours. The relative speed when traveling in the same direction is \( x - y \). The distance covered is 160 km. \[ \text{Distance} = \text{Speed} \times \text{Time} \] \[ 160 = (x - y) \times 8 \] Dividing both sides by 8: \[ x - y = 20 \quad \text{(Equation 1)} \] 2. **Towards Each Other:** When both cars travel towards each other, they meet after 2 hours. The relative speed when traveling towards each other is \( x + y \). \[ 160 = (x + y) \times 2 \] Dividing both sides by 2: \[ x + y = 80 \quad \text{(Equation 2)} \] ### Step 2: Solve the equations. Now we have a system of two equations: 1. \( x - y = 20 \) (Equation 1) 2. \( x + y = 80 \) (Equation 2) We can solve these equations simultaneously. **Adding Equation 1 and Equation 2:** \[ (x - y) + (x + y) = 20 + 80 \] \[ 2x = 100 \] \[ x = 50 \quad \text{(Speed of the first car)} \] **Substituting \( x \) back into Equation 1 to find \( y \):** \[ 50 - y = 20 \] \[ y = 50 - 20 \] \[ y = 30 \quad \text{(Speed of the second car)} \] ### Conclusion: The speed of the first car is \( 50 \) km/h, and the speed of the second car is \( 30 \) km/h.
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RS AGGARWAL-LINEAR EQUATIONS IN TWO VARIABLES -Exercise 3E
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