If (2x + y + 2)/(5) = ( 3x - y + 1)/...

If `(2x + y + 2)/(5) = ( 3x - y + 1)/( 3 ) = ( 2 x + 2y + 1 )/(6) ` then

` x = 1, y = 1 `

` x = - 1, y = - 1 `

`x = 1 , y = 2 `

` x = 2, y = 1 `

Text Solution

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The correct Answer is:

` ( 2x + y + 2 )/( 5) = (3x - y + 1)/(3) rArr 6x + 3y + 6 = 15x - 5y + 5 rArr 9x - 8y = 1 " " ` ... (i)
`(3x - y + 1 )/(3) = ( 3x + 2y + 1 )/(6) rArr 18x - 6y + 6 = 9x + 6y + 3 rArr 9x - 12 y = - 3" " ` ... (ii)
Solve (i) and (ii) to get ` x = 1 and y = 1 `

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