Solve the following quadratic equation for `x:4x^2 + 4bx – (a^2-b^2) = 0`

Answer

`x=(-(a+b))/(2)" or "x=(a-b)/(2)`

Explanation

`4x^(2)+4bx+(b^(2)-a^(2))=0implies4x^(2)+2(b+a)x+2(b-a)x+(b^(2)-a^(2))=0.`