If a and b are real and `aneb` then show that the roots of the equation `(a-b)x^(2)+5(a+b)x-2(a-b)=0` are real and unequal.

Explanation

To show that the roots of the equation \((a-b)x^2 + 5(a+b)x - 2(a-b) = 0\) are real and unequal, we will use the discriminant method. The discriminant \(D\) of a quadratic equation \(Ax^2 + Bx + C = 0\) is given by \(D = B^2 - 4AC\). The roots are real and unequal if \(D > 0\).

### Step-by-Step Solution:

1. **Identify coefficients**:
For the equation \((a-b)x^2 + 5(a+b)x - 2(a-b) = 0\), we identify:
- \(A = a - b\)
- \(B = 5(a + b)\)
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