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Three consecutive positive integers are such that the sum of the square of the first and the product of other two is 46, fond the integers.

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The correct Answer is:
4,5,6

Let the required numbers be `x,(x+1)" and "(x+2).` Then,
`x^(2)+(x+1)(x+2)=46implies2x^(2)+3x-44=0implies2x^(2)+11x-8x-44=0`
`implies(2x+11)(x-4).`
`xne(-11)/(2)`, since x is an integer.
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