The length of a rectangle is twice its breadth and its area is 288 `cm^(2)`.
Find the dimensions of the rectangle.

Explanation

To find the dimensions of the rectangle, we can follow these steps:

### Step 1: Define the variables
Let the breadth of the rectangle be \( B \) cm. According to the problem, the length \( L \) is twice the breadth. Therefore, we can express the length as:
\[ L = 2B \]

### Step 2: Write the formula for the area of the rectangle
The area \( A \) of a rectangle is given by the formula:
\[ A = L \times B \]
We know from the problem that the area is \( 288 \, cm^2 \). Substituting the expression for length into the area formula, we get:
\[ A = (2B) \times B = 2B^2 \]

### Step 3: Set up the equation
Now, we can set up the equation using the area:
\[ 2B^2 = 288 \]

### Step 4: Solve for \( B^2 \)
To isolate \( B^2 \), divide both sides of the equation by 2:
\[ B^2 = \frac{288}{2} = 144 \]

### Step 5: Find \( B \)
Now, take the square root of both sides to find \( B \):
\[ B = \sqrt{144} = 12 \, cm \]

### Step 6: Find \( L \)
Now that we have the breadth, we can find the length using the relationship \( L = 2B \):
\[ L = 2 \times 12 = 24 \, cm \]

### Conclusion
The dimensions of the rectangle are:
- Breadth \( B = 12 \, cm \)
- Length \( L = 24 \, cm \)