The area of a right angled triangle is `600c m^2dot` If the base of the triangle exceeds the altitude by 10cm, find the dimensions of the triangle.

Answer

`30 cm,40 cm,50 cm`

Explanation

Let the altitude be x cm. Then, base `=(x+10)cm.`
`:." "(1)/(2)(x+10)x=600impliesx^(2)+10x-1200=0`
`implies" "(x+40)(x-30)=0impliesx=30.`
`:." ""base = 40 cm, altitude = 30 cm."`
`:." "" hypotenuse "=sqrt((40)^(2)+(30)^(2)))=sqrt(1600+900)=sqrt(2500)=50cm.`