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The perimeter of a rectangle is 82 m and...

The perimeter of a rectangle is 82 m and its area is `400 m^(2)`. The breadth of the rectangle is

A

25 m

B

20 m

C

16 m

D

9 m

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To find the breadth of the rectangle given the perimeter and area, we can follow these steps: ### Step 1: Understand the formulas The perimeter \( P \) of a rectangle is given by: \[ P = 2(l + b) \] where \( l \) is the length and \( b \) is the breadth. The area \( A \) of a rectangle is given by: \[ A = l \times b \] ### Step 2: Set up the equations From the problem, we know: 1. The perimeter \( P = 82 \) m 2. The area \( A = 400 \) m² Using the perimeter formula: \[ 2(l + b) = 82 \] Dividing both sides by 2: \[ l + b = 41 \quad \text{(Equation 1)} \] Using the area formula: \[ l \times b = 400 \quad \text{(Equation 2)} \] ### Step 3: Express one variable in terms of the other From Equation 1, we can express \( l \) in terms of \( b \): \[ l = 41 - b \] ### Step 4: Substitute into the area equation Substituting \( l \) in Equation 2: \[ (41 - b) \times b = 400 \] Expanding this gives: \[ 41b - b^2 = 400 \] ### Step 5: Rearranging the equation Rearranging the equation to standard quadratic form: \[ b^2 - 41b + 400 = 0 \] ### Step 6: Factor the quadratic equation We need to factor the quadratic equation: \[ b^2 - 25b - 16b + 400 = 0 \] This can be factored as: \[ (b - 25)(b - 16) = 0 \] ### Step 7: Solve for \( b \) Setting each factor to zero gives us: 1. \( b - 25 = 0 \) → \( b = 25 \) 2. \( b - 16 = 0 \) → \( b = 16 \) ### Step 8: Determine the dimensions Since \( l + b = 41 \): - If \( b = 25 \), then \( l = 41 - 25 = 16 \) - If \( b = 16 \), then \( l = 41 - 16 = 25 \) ### Conclusion The breadth of the rectangle is: \[ \text{Breadth} = 16 \text{ m} \]

To find the breadth of the rectangle given the perimeter and area, we can follow these steps: ### Step 1: Understand the formulas The perimeter \( P \) of a rectangle is given by: \[ P = 2(l + b) \] where \( l \) is the length and \( b \) is the breadth. ...
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