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The roots of the quadratic equation 2x^2...

The roots of the quadratic equation `2x^2 - x - 6 = 0` are

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The correct Answer is:
`x=2" or "x=(-3)/(2)`
`2x^(2)-x-6=0implies2x^(2)-4x+3x-6=0implies2x(x-2)+3(x-2)=0`
`implies(x-2)(2x+3)=0impliesx=2" or "x=(-3)/(2).`
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RS AGGARWAL-QUADRATIC EQUATIONS -Test Yourself
  1. Show that x=-2 is a solution of 3x^(2)+13x+14=0.

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  2. If x=-(1)/(2) is a solution of the quadratic equation 3x^(2)+2kx-3=0, ...

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  3. The roots of the quadratic equation 2x^2 - x - 6 = 0 are

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  4. Find the discriminant of the quadratic equation 3sqrt3x^2+10x+sqrt3=0.

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  8. If one zero of the polynomial x^3-4x+1 is 2+sqrt3 write the other zero

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  9. If one root of the quadratic equation 3x^(2)-10x+k=0 is reciprocal of ...

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  10. Find the value of p for which the roots of the equation px (x — 2) + 6...

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  11. Find the value(s) of k so that, the quadratic equation x^2 - 4kx + k =...

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  13. Solve: x^2-(sqrt3+1)x+sqrt3 = 0

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  16. Solve : sqrt(3)x^(2)+10x-8sqrt(3)=0.

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  17. Solve for x sqrt3x^2-2sqrt(2)x-2sqrt3=0

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  18. Solve by factorization: 4sqrt(3)x^2+5x-2sqrt(3)=0

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  19. Solve by factorization: 4x^2+4b x-(a^2-b^2)=0

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  20. Solve x^(2)+5x-(a^(2)+a-6)=0.

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