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Find the value of p for which the roots ...

Find the value of p for which the roots of the equation px (x — 2) + 6 = 0, are equal.

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The correct Answer is:
p=6
Given equation is `px^(2)-2px+6=0.`
This is of the form `ax^(2)+bx+c=0,` where `a=p,b=-2p` and `c=6.`
`:." "D=(b^(2)-4ac)=4p^(2)-24p.`
For equal roots, we have `D=0.`
`:." "4p^(2)-24p=0implies4p(p-6)=0impliesp=6." "[becausepne0]`
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