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In the given figure, an isosceles triang...

In the given figure, an isosceles triangle `ABC`, with `AB=AC`, circumscribes a circle. Prove that the point of contact `P` bisects the base `BC`.

Text Solution

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We know that the tangents to a circle from an external point are equal.
`:.AQ=AR`, `BP=BR`, `CP=CQ`.
Now, `AB=ACimpliesAR+BR=AQ+CQ`
`impliesAR+BP=AR+CPimpliesBP=CP`
`implies P` bisects the base `BC`.
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