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In figure, O is the centre of a circle. ...

In figure, O is the centre of a circle. PT and PQ are tangents to the circle from an external point P. If `angleTPQ=70^(@)`, find `angleTRQ`.

Text Solution

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Join `OT` and `OQ`.
Then, `/_TOQ+/_TPQ=180^(@)implies/_TOQ=180^(@)-70^(@)=110^(@)`
Now, `/TRQ=(1)/(@)xx/_TOQ=(1)/(2)xx110^(@)=55^(@)` [`:'` the angle subtended by an arc of a circle at the centre is double the angle subtended by it any point on the remaining part of the circle.]
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