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PQ is a tangent to a circle with centre ...

`PQ` is a tangent to a circle with centre `O` at the point `P`. If `DeltaOPQ` is an isoceless triangle, then `/_OQP` is equal to

A

`30^(@)`

B

`45^(@)`

C

`60^(@)`

D

`90^(@)`

Text Solution

Verified by Experts

We have `OPbotPQ`, i.e., `/_OPQ=90^(@)`
`DeltaOPQ` is isosceles `impliesOP=PQimplies/_OQP=/_POQ=45^(@)`
[`:'` in a triangle, angles opposite equal sides are equal].
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