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In the given figure, `O` is the centre of a circle, `PQ` is a chord and `PT` is the tangent at `P`. If `/_POQ=70^(@)`, then `/_TPQ` is equal to

A

`35^(@)`

B

`45^(@)`

C

`55^(@)`

D

`70^(@)`

Text Solution

Verified by Experts

Mark a point `R` in the alternate segment.
Join `PR` and `QR`.
Then, `/_PRQ=(1)/(2)/_POQ=(1)/(2)xx70^(@)=35^(@)`.
Now, `/_TPQ=/_PRQ=35^(@)`[angles in alternate segments].
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