In the given figure, DE and DF are tange...

In the given figure, `DE` and `DF` are tangents from and external point `D` to a circle with centre `A`. If `DE=5cm` and `DEbotDF` then the radius of the circle is

`3cm`

`4cm`

`5cm`

`6cm`

Text Solution

Verified by Experts

Join `AE` and `AF`. Then , `AFDE` is a square
`:.` radius of circle `=AE=DE=5cm`.

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